Small group number 1755 of order 128
G = 64gp138xC2 is Direct product 64gp138 x C_2
G has 4 minimal generators, rank 5 and exponent 4.
The centre has rank 2.
There are 5 conjugacy classes of maximal
elementary abelian subgroups. Their ranks are:
4, 4, 4, 4, 5.
This cohomology ring calculation is complete.
Ring structure
| Completion information
| Koszul information
| Restriction information
| Poincaré series
The cohomology ring has 9 generators:
- y1 in degree 1
 
- y2 in degree 1
 
- y3 in degree 1
 
- y4 in degree 1, a regular element
 
- x1 in degree 2
 
- x2 in degree 2
 
- x3 in degree 2
 
- w in degree 3
 
- v in degree 4, a regular element
 
There are 9 minimal relations:
- y2.y3 =
0
 
- y1.y3 =
0
 
- y2.x2 =
y1.x1
 
- y2.x1 =
y1.x1
 
- y1.x3 =
y1.x1
 
- x2.x3 =
x12
+ y3.w
 
- y2.w =
0
 
- y1.w =
0
 
- w2 =
x12.x3
+ x12.x2
+ y3.x1.w
+ y32.v
 
A minimal Gröbner basis for the relations ideal
consists of this minimal generating set, together with the
following redundant relation:
This cohomology ring was obtained from a calculation
out to degree 13. The cohomology ring approximation
is stable from degree 6 onwards, and
Benson's tests detect stability from degree 13
onwards.
This cohomology ring has dimension 5 and depth 4.
Here is a homogeneous system of parameters:
- h1 =
y4
in degree 1
 
- h2 =
v
in degree 4
 
- h3 =
x32
+ x22
+ x12
+ y3.w
+ y34
+ y24
+ y12.y22
+ y14
in degree 4
 
- h4 =
x12.x3
+ x12.x2
+ y3.x3.w
+ y3.x2.w
+ y32.x32
+ y32.x22
+ y32.x12
+ y33.w
+ y22.x32
+ y12.x22
+ y12.x12
+ y12.y24
+ y14.y22
in degree 6
 
- h5 =
y3
in degree 1
 
The first
4 terms h1, h2, h3, h4 form
a regular sequence of maximum length.
The first
2 terms h1, h2 form
a complete Duflot regular sequence.
That is, their restrictions to the greatest central elementary abelian
subgroup form a regular sequence of maximal length.
Data for Benson's test:
- 
Raw filter degree type:
-1, -1, -1, -1, 10, 11.
 - 
Filter degree type:
-1, -2, -3, -4, -5, -5.
 - 
α = 0
 - 
The system of parameters is very strongly quasi-regular.
 - 
The regularity conjecture is satisfied.
 
A basis for R/(h1, h2, h3, h4, h5) is as follows.
- 
1
in degree 0
 
- 
y2
in degree 1
 
- 
y1
in degree 1
 
- 
x3
in degree 2
 
- 
x2
in degree 2
 
- 
x1
in degree 2
 
- 
y22
in degree 2
 
- 
y1.y2
in degree 2
 
- 
y12
in degree 2
 
- 
w
in degree 3
 
- 
y2.x3
in degree 3
 
- 
y23
in degree 3
 
- 
y1.x2
in degree 3
 
- 
y1.x1
in degree 3
 
- 
y1.y22
in degree 3
 
- 
y12.y2
in degree 3
 
- 
y13
in degree 3
 
- 
x22
in degree 4
 
- 
x1.x3
in degree 4
 
- 
x1.x2
in degree 4
 
- 
x12
in degree 4
 
- 
y22.x3
in degree 4
 
- 
y24
in degree 4
 
- 
y1.y23
in degree 4
 
- 
y12.x2
in degree 4
 
- 
y12.x1
in degree 4
 
- 
y12.y22
in degree 4
 
- 
y13.y2
in degree 4
 
- 
y14
in degree 4
 
- 
x3.w
in degree 5
 
- 
x2.w
in degree 5
 
- 
x1.w
in degree 5
 
- 
y23.x3
in degree 5
 
- 
y25
in degree 5
 
- 
y1.x12
in degree 5
 
- 
y1.y24
in degree 5
 
- 
y12.y23
in degree 5
 
- 
y13.x2
in degree 5
 
- 
y13.x1
in degree 5
 
- 
y13.y22
in degree 5
 
- 
y14.y2
in degree 5
 
- 
y15
in degree 5
 
- 
x1.x22
in degree 6
 
- 
x12.x2
in degree 6
 
- 
x13
in degree 6
 
- 
y24.x3
in degree 6
 
- 
y26
in degree 6
 
- 
y12.x12
in degree 6
 
- 
y12.y24
in degree 6
 
- 
y13.y23
in degree 6
 
- 
y14.x2
in degree 6
 
- 
y14.x1
in degree 6
 
- 
y14.y22
in degree 6
 
- 
y15.y2
in degree 6
 
- 
y16
in degree 6
 
- 
x22.w
in degree 7
 
- 
x1.x3.w
in degree 7
 
- 
x1.x2.w
in degree 7
 
- 
x12.w
in degree 7
 
- 
y25.x3
in degree 7
 
- 
y13.x12
in degree 7
 
- 
y13.y24
in degree 7
 
- 
y14.y23
in degree 7
 
- 
y15.x2
in degree 7
 
- 
y15.x1
in degree 7
 
- 
y15.y22
in degree 7
 
- 
y16.y2
in degree 7
 
- 
x13.x2
in degree 8
 
- 
y26.x3
in degree 8
 
- 
y14.x12
in degree 8
 
- 
y14.y24
in degree 8
 
- 
y15.y23
in degree 8
 
- 
y16.x2
in degree 8
 
- 
y16.x1
in degree 8
 
- 
y16.y22
in degree 8
 
- 
x1.x22.w
in degree 9
 
- 
x12.x2.w
in degree 9
 
- 
x13.w
in degree 9
 
- 
y15.x12
in degree 9
 
- 
y15.y24
in degree 9
 
- 
y16.y23
in degree 9
 
- 
y16.x12
in degree 10
 
- 
y16.y24
in degree 10
 
- 
x13.x2.w
in degree 11
 
A basis for AnnR/(h1, h2, h3, h4)(h5) is as follows.
- 
y2
in degree 1
 
- 
y1
in degree 1
 
- 
y22
in degree 2
 
- 
y1.y2
in degree 2
 
- 
y12
in degree 2
 
- 
y2.x3
in degree 3
 
- 
y23
in degree 3
 
- 
y1.x2
in degree 3
 
- 
y1.x1
in degree 3
 
- 
y1.y22
in degree 3
 
- 
y12.y2
in degree 3
 
- 
y13
in degree 3
 
- 
y22.x3
in degree 4
 
- 
y24
in degree 4
 
- 
y1.y23
in degree 4
 
- 
y12.x2
in degree 4
 
- 
y12.x1
in degree 4
 
- 
y12.y22
in degree 4
 
- 
y13.y2
in degree 4
 
- 
y14
in degree 4
 
- 
y23.x3
in degree 5
 
- 
y25
in degree 5
 
- 
y1.x12
in degree 5
 
- 
y1.y24
in degree 5
 
- 
y12.y23
in degree 5
 
- 
y13.x2
in degree 5
 
- 
y13.x1
in degree 5
 
- 
y13.y22
in degree 5
 
- 
y14.y2
in degree 5
 
- 
y15
in degree 5
 
- 
y24.x3
in degree 6
 
- 
y26
in degree 6
 
- 
y12.x12
in degree 6
 
- 
y12.y24
in degree 6
 
- 
y13.y23
in degree 6
 
- 
y14.x2
in degree 6
 
- 
y14.x1
in degree 6
 
- 
y14.y22
in degree 6
 
- 
y15.y2
in degree 6
 
- 
y16
in degree 6
 
- 
y25.x3
in degree 7
 
- 
y13.x12
in degree 7
 
- 
y13.y24
in degree 7
 
- 
y14.y23
in degree 7
 
- 
y15.x2
in degree 7
 
- 
y15.x1
in degree 7
 
- 
y15.y22
in degree 7
 
- 
y16.y2
in degree 7
 
- 
y26.x3
in degree 8
 
- 
y14.x12
in degree 8
 
- 
y14.y24
in degree 8
 
- 
y15.y23
in degree 8
 
- 
y16.x2
in degree 8
 
- 
y16.x1
in degree 8
 
- 
y16.y22
in degree 8
 
- 
y15.x12
in degree 9
 
- 
y15.y24
in degree 9
 
- 
y16.y23
in degree 9
 
- 
y16.x12
in degree 10
 
- 
y16.y24
in degree 10